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Downside 1
I learn this was a PSAT query, which is a standardized take a look at given to US college students aged about 15 or 16 who almost certainly haven’t taken a course in trigonometry.
If every of the three semicircles beneath has an space equal to 72, and is the midpoint of , what’s the space of the shaded area?
Downside 2
That is tailored from the 2020 AMC 10B, downside 14.
An everyday hexagon with facet size 2 has semicircles constructed in its inside of every facet. What’s the shaded space contained in the hexagon not lined by the semicircles?
Downside 3
Because of Andrei for the suggestion!
A sq. has a facet size of seven. On every nook, 1 / 4 circle with radius 3 is constructed with the nook as its middle. And on the midpoint of every facet, a semicircle with radius 2 is constructed with the midpoint as its middle. What’s the distinction between the orange shaded areas and the blue shaded areas?
As standard, watch the video for options.
3 Puzzles About Shaded Areas And Circles
Or preserve studying.
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“All might be properly should you use your thoughts in your selections, and thoughts solely your selections.” Since 2007, I’ve devoted my life to sharing the enjoyment of sport idea and arithmetic. MindYourDecisions now has over 1,000 free articles with no advertisements due to neighborhood assist! Assist out and get early entry to posts with a pledge on Patreon.
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Reply To PSAT Query Three Semicircles
(Just about all posts are transcribed shortly after I make the movies for them–please let me know if there are any typos/errors and I’ll appropriate them, thanks).
Thanks Erik for alerting me of typos!
Downside 1
There’s a remarkably simple technique to calculate the world!
Since Q is the midpoint of the diameter PR, it’s the middle of the left semicircle. Because the three semicircles have the identical space, all three are congruent. The 2 semicircles on the appropriate go via Q, so their intersections with semicircle Q might be congruent and have the identical space. Thus the 2 inexperienced areas are equal in space and can cancel out within the calculation.
Thus the world of the claw is the same as the world of a 20 diploma sector. Since every semicircle has 180 levels, and an space of 72, the reply is:
space claw
= space 20 diploma sector
= 72(20/180)
= 8
That’s it!
Downside 2
Divide the hexagon right into a grid of equilateral triangles of facet size 1, as proven. The shaded space is then 6 instances the world of a single blue slice.
However every blue slice is the same as the world of two equilateral triangles minus a round sector with a central angle equal to 1. Each the triangles have a facet of 1 and the circle has a radius of 1.
A single blue slice has space equal to:
2(s2√3)/4 – πr2(60/360)
= 2(√3)/4 – π/6
= (3√3 – π)/6
This space instances 6 provides the shaded space as 3√3 – π ≈ 2.05.
Downside 3
At first I had tried to calculate the world of the overlapping area. However it is a far too difficult computation. So I assumed there should be one other technique.
Let every of the orange areas be equal to a, the overlapping areas be b, and the blue areas be c.
We wish to calculate:
4a – 4c
However we do know:
a + 2b = space quarter circle
c + 2b = space semicircle
Multiplying every equation by 4 and subtracting provides:
4a – 4c
= 4(space quarter circle) – 4(space semicircle)
= 4(π32/4) – 4(π22/2)
= π
And like magic we now have discovered the reply!
I obtained a pleasant electronic mail from Atanas who has developed code in 3 languages if you wish to simulate this end result your self! Test it out on Github: https://github.com/batinkov/simulations/tree/principal/2_puzzles_about_shuffling_cards
Sources
Downside 1
Math StackExchange
https://math.stackexchange.com/questions/2334447/area-of-intersection-of-three-circles
Downside 2
AoPS
https://artofproblemsolving.com/wiki/index.php/2020_AMC_10B_Problems/Problem_14
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